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If rope of lift breaks suddenly, the tension exerted by the surface of the lift (a = Acceleration of lift) is
Options
(a) mg
(b) m(g+a)
(c) zero
(d) m(g-a)
Correct Answer:
zero
Explanation:
If the rope suddenly breaks, acceleration = g
So substituting in formula, tension T=m(g−a)=0
Related Questions: - A mass m moving horizontally (along the x-axis) with velocity v collides and sticks
- In a discharge tube ionization of enclosed gas is produced due to collisions between
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Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A mass m moving horizontally (along the x-axis) with velocity v collides and sticks
- In a discharge tube ionization of enclosed gas is produced due to collisions between
- An objective moves ,starting from rest through a resistive medium
- A 50Hz AC signal is applied in a circuit of inductance of (1/π)H and resistance 2100Ω
- X-ray beam can be deflected by
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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