| ⇦ | 
| ⇨ |
A block of 2 kg is kept on the floor. The coefficient of static friction is 0.4. If a force F of 2.5 newton is applied on the block, the frictional force between the block and the floor will be
Options
(a) 2.5 N
(b) 5 N
(c) 10 N
(d) 7.84 N
Correct Answer:
2.5 N
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The numebr 0 (zero) is required for
- A particle free to move along X-axis has potential energy given as U(X) =k(1-e⁻ˣ²)
- If light emitted from sodium bulb is passed through sodium vapour,
- Match the following columns about collision
- Two conducting spheres of radii 5 cm and 10 cm are given a charge of 15 μC each.
Topics: Laws of Motion
(103)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The numebr 0 (zero) is required for
- A particle free to move along X-axis has potential energy given as U(X) =k(1-e⁻ˣ²)
- If light emitted from sodium bulb is passed through sodium vapour,
- Match the following columns about collision
- Two conducting spheres of radii 5 cm and 10 cm are given a charge of 15 μC each.
Topics: Laws of Motion (103)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply