| ⇦ | 
| ⇨ |
If ionization potential for hydrogen atom is 13.6eV, then ionization potential for He⁺ will be
Options
(a) 54.4 eV
(b) 6.8 eV
(c) 13.6 eV
(d) 24.5 eV
Correct Answer:
54.4 eV
Explanation:
The ionization energy of any hydrogen like species (having one electron only) is given by the equation I.E = (2π²Z²me⁴)/h². Since the atomic number of H is 1 and that of He is 2, therefore,the I.E. of He⁺ is four times = Z²=(2²) the I.E. of H. So, 13.6 x 4= 54.4 eV
Related Questions: - Ozone is formed in the upper atmosphere from oxygen by the action of
- What is the equivalent mass of IO₄⁻ when it is converted into I₂ in acid medium
- The two electrons in K-subshell will differ in
- Which of the following acids exhibits optical activity
- The isomerism represented by ethyl acetoacetate is
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Ozone is formed in the upper atmosphere from oxygen by the action of
- What is the equivalent mass of IO₄⁻ when it is converted into I₂ in acid medium
- The two electrons in K-subshell will differ in
- Which of the following acids exhibits optical activity
- The isomerism represented by ethyl acetoacetate is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply