| ⇦ | 
| ⇨ |
The correct set of four quantum numbers for the valence electron of rubidium atom(Z=37) is
Options
(a) 5,1,1,+½
(b) 6,0,0,+½
(c) 5,0,0,+½
(d) 5,1,0,+½
Correct Answer:
5,0,0,+½
Explanation:
₃₇Rb=₃₆[Kr] 5s
Its valence electron in 5s¹.
so, n= 5
/= 0 (For s oribital)
m= 0 (As m= -/ to 0 to +/)
s= +½.
Related Questions: - When acetone reacts with bleaching powder, the compound formed is
- Which of the following corresponds to the electronic configuration 1s², 2s²,2p⁶
- When 10 mL of 0.1 M acetic acid (pKa = 5.0 ) is titrated against 10mL of 0.1 M
- If avagadro number is changed what changes
- Dumas method is used for the estimation of
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- When acetone reacts with bleaching powder, the compound formed is
- Which of the following corresponds to the electronic configuration 1s², 2s²,2p⁶
- When 10 mL of 0.1 M acetic acid (pKa = 5.0 ) is titrated against 10mL of 0.1 M
- If avagadro number is changed what changes
- Dumas method is used for the estimation of
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply