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The correct set of four quantum numbers for the valence electron of rubidium atom(Z=37) is
Options
(a) 5,1,1,+½
(b) 6,0,0,+½
(c) 5,0,0,+½
(d) 5,1,0,+½
Correct Answer:
5,0,0,+½
Explanation:
₃₇Rb=₃₆[Kr] 5s
Its valence electron in 5s¹.
so, n= 5
/= 0 (For s oribital)
m= 0 (As m= -/ to 0 to +/)
s= +½.
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- Which of the following transition element shows the highest oxidation state
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Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Structure of Atom
(90)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Oxidation number of iron in [Fe(CN)₆]⁴⁻ is
- Which of the following transition element shows the highest oxidation state
- In the periodic table, the element with atomic number 16 will be placed
- The internal energy of a system is the sum of
- General electronic configuration of lanthanides is
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Structure of Atom (90)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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