| ⇦ | 
| ⇨ |
If a magnet is suspended at an angle 30⁰ to the magnetic meridian, the dip needle makes angle of 45⁰ with the horizontal. The real dip is
Options
(a) tan⁻¹(√3/2)
(b) tan⁻¹(√3)
(c) tan⁻¹(3/√2)
(d) tan⁻¹(2/√3)
Correct Answer:
tan⁻¹(2/√3)
Explanation:
tan δ’ = tan δ / cos θ = tan 45° / cos 30°
tan δ’ = 1 / (√3/2) = 2 / √3
δ’ = tan⁻¹ (2 / √3)
Related Questions: - A uniform chain of length L and mass m is kept on a smooth table. It is released
- Number of electrons in one mC charge, given e=1.6×10⁻¹⁹ C, will be
- Find the right condition(s) for Fraunhofer diffraction due to a single slit.
- There is a ring of radius r having linear charge densityλ and rotating with a uniform
- Three solids of masses m₁,m₂ and m₃ are connected with weightless string
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A uniform chain of length L and mass m is kept on a smooth table. It is released
- Number of electrons in one mC charge, given e=1.6×10⁻¹⁹ C, will be
- Find the right condition(s) for Fraunhofer diffraction due to a single slit.
- There is a ring of radius r having linear charge densityλ and rotating with a uniform
- Three solids of masses m₁,m₂ and m₃ are connected with weightless string
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply