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If a carnot engine is working with source temperature at 227⁰C and sink temperature at 27⁰C, its efficiency will be
Options
(a) 40%
(b) 10%
(c) 67%
(d) 50%
Correct Answer:
40%
Explanation:
Efficiency of a Carnot engine η = 1 – (T₂ / T₁)
where T₁ is the temperature of the source and T₂ is the temperature of the sink.
Here, T₁ = 227°C = 500 K
T₂ = 27°C = 300 K
.·. η = 1 – (300/500) = 2/5 = 40 %.
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Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In India, electricity is supplied for domestic use at 200V. It is supplied at 110 V
- Assertion(A) :The change in kinetic energy of a particle is equal to the work done
- Two points are located at a distance of 10 m and 15 m from the source of oscillation
- The electric field in a certain region is acting radially outward and is given by E=Ar.
- The optical path of a monochromatic light is same if it goes through 4.0 cm
Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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