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If a carnot engine is working with source temperature at 227⁰C and sink temperature at 27⁰C, its efficiency will be
Options
(a) 40%
(b) 10%
(c) 67%
(d) 50%
Correct Answer:
40%
Explanation:
Efficiency of a Carnot engine η = 1 – (T₂ / T₁)
where T₁ is the temperature of the source and T₂ is the temperature of the sink.
Here, T₁ = 227°C = 500 K
T₂ = 27°C = 300 K
.·. η = 1 – (300/500) = 2/5 = 40 %.
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Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A change of 0.04 V takes place between the base and the emitter when an input
- When an object is placed 40cm from a diverging lens, its virtual image is formed 20 cm
- The phase difference between the flux linked with a coil rotating in a uniform
- When the rate of flow of charge through a metallic conductor
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Topics: Thermodynamics (179)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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