| ⇦ | 
| ⇨ |
If a carnot engine is working with source temperature at 227⁰C and sink temperature at 27⁰C, its efficiency will be
Options
(a) 40%
(b) 10%
(c) 67%
(d) 50%
Correct Answer:
40%
Explanation:
Efficiency of a Carnot engine η = 1 – (T₂ / T₁)
where T₁ is the temperature of the source and T₂ is the temperature of the sink.
Here, T₁ = 227°C = 500 K
T₂ = 27°C = 300 K
.·. η = 1 – (300/500) = 2/5 = 40 %.
Related Questions:
- A particle is moving such that its position coordinates (x,y) are (2 m,3 m) at time
- Two equal and opposite charges of masses m₁ and m₂ are accelerated
- The electirc field in a certain region is acting radially outward and is given by E=Ar.
- A battery of e.m.f. E and internal resistance r is connected to an external resistance
- Source S₁ is producing, 10¹⁵ photons per second of wavelength 5000Å
Topics: Thermodynamics
(179)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply