If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is

If 15230 And 15145 Then Dispersive Power Of Crown Glass Physics Question

If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is

Options

(a) 0.0164
(b) 0.00701
(c) 0.0132
(d) 0.032

Correct Answer:

0.0164

Explanation:

Here μᵥ=1.5230and μʀ=1.5145

Therefore, mean refractive index, μ =(1.523+1.5145) /2 = 1.5187

Now, dispersive power, ω is given by,

ω =(μᵥ-μʀ)/(μ-1) =(1.5230 – 1.5145)/(1.5187 – 1) =0.0164

Related Questions:

  1. A charged oil drop is suspended in a uniform field at 3×10⁴ V/m so that it neither falls
  2. If alpha, beta and gamma rays carry same momentum, which has the longest
  3. Which of the following is a vector quantity?
  4. Photons of energy 6 eV are incident on a metal surface whose work function is 4 eV.
  5. Minimum and maximum values of Poisson’s ratio for a metal lies between

Topics: Ray Optics (94)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*