| ⇦ | 
| ⇨ |
Given the value of Rydberg constant is 10⁷ m⁻¹, the wave number of the last line of the Balmer series in hydrogen spectrum will be
Options
(a) 0.5×10⁷ m⁻¹
(b) 0.25×10⁷ m⁻¹
(c) 2.5×10⁷ m⁻¹
(d) 0.025×10⁷ m⁻¹
Correct Answer:
0.25×10⁷ m⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Three capacitors each of capacitance C and of breakdown voltage V are joined in series
- The potential energy of a long spring when stretched by 2 cm is U.
- The electric field associated with an e.m. wave in vacuum is given by
- A parallel beam of fast moving electrons is incident normally on a narrow slit.
- A potentiometer wire of length 100cm has a resistance of 10Ω. It is connected in series
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Three capacitors each of capacitance C and of breakdown voltage V are joined in series
- The potential energy of a long spring when stretched by 2 cm is U.
- The electric field associated with an e.m. wave in vacuum is given by
- A parallel beam of fast moving electrons is incident normally on a narrow slit.
- A potentiometer wire of length 100cm has a resistance of 10Ω. It is connected in series
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply