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Given the value of Rydberg constant is 10⁷ m⁻¹, the wave number of the last line of the Balmer series in hydrogen spectrum will be
Options
(a) 0.5×10⁷ m⁻¹
(b) 0.25×10⁷ m⁻¹
(c) 2.5×10⁷ m⁻¹
(d) 0.025×10⁷ m⁻¹
Correct Answer:
0.25×10⁷ m⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into
- ₉₂U²³⁴ has 92 protons and 238 nucleons. It decays by emitting an alpha particle
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- The velocity of radio-waves is 3×10⁵ km/s. The frequency corresponding to wavelength
- The ratio of minimum wavelengths of Lyman and Balmer series will be
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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