| ⇦ | 
| ⇨ |
Given the value of Rydberg constant is 10⁷ m⁻¹, the wave number of the last line of the Balmer series in hydrogen spectrum will be
Options
(a) 0.5×10⁷ m⁻¹
(b) 0.25×10⁷ m⁻¹
(c) 2.5×10⁷ m⁻¹
(d) 0.025×10⁷ m⁻¹
Correct Answer:
0.25×10⁷ m⁻¹
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions:
- A man measures time period of a pendulum(T) in stationary lift. If the lift moves upwards
- Electrons with energy 80 keV are incident on the tungsten target of an X-ray tube.
- Ratio of longest wavelengths corresponding to Lyman and Balmer series in hydrogen
- The p-type semiconductor is
- The pressure at the bottom of a tank containing a liquid does not depend on
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply