| ⇦ | 
| ⇨ |
For photoelectric emission from certain metal the cut-off frequency is v. If radiation of frequency 2v impinges on the metal plate, the maximum possible velocity of the emitted electron will be (m is the electron mass)
Options
(a) √ hv / m
(b) √ 2hv / m
(c) 2 √hv / m
(d) √ hv / (2m)
Correct Answer:
√ 2hv / m
Explanation:
From photo-electric equation,
hv’ = hv + Kₘₐₓ …(i)
h.2v = hv + 1/2 mV²ₘₐₓ [ v’ = 2v ]
hv = 1/2 mV²ₘₐₓ ⇒ Vₘₐₓ = √ 2hv / m
Related Questions: - A body of mass 2 kg is kept by pressing to a vertical wall by a force of 100 N
- In Young’s double slit experiment the distance between the slits and the screen
- A body takes 5 minute for cooling from 50⁰C to 40⁰C. Its temperature
- If the series limit of Lyman series for hydrogen atom is equal to the series limit
- A ball is thrown vertically downwards from a height of 20 m with an initially
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body of mass 2 kg is kept by pressing to a vertical wall by a force of 100 N
- In Young’s double slit experiment the distance between the slits and the screen
- A body takes 5 minute for cooling from 50⁰C to 40⁰C. Its temperature
- If the series limit of Lyman series for hydrogen atom is equal to the series limit
- A ball is thrown vertically downwards from a height of 20 m with an initially
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply