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For photoelectric emission from certain metal the cut-off frequency is v. If radiation of frequency 2v impinges on the metal plate, the maximum possible velocity of the emitted electron will be (m is the electron mass)
Options
(a) √ hv / m
(b) √ 2hv / m
(c) 2 √hv / m
(d) √ hv / (2m)
Correct Answer:
√ 2hv / m
Explanation:
From photo-electric equation,
hv’ = hv + Kₘₐₓ …(i)
h.2v = hv + 1/2 mV²ₘₐₓ [ v’ = 2v ]
hv = 1/2 mV²ₘₐₓ ⇒ Vₘₐₓ = √ 2hv / m
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- 64 drops of mercury, each charged to a potential of 10 V, are combined
- The capacitance of two concentric spherical shells of radii R₁ and R₂ (R₂>R₁) is
- In which of the following systems will the radius of the first orbit (n=1) be minimum?
- Two simple harmonic motions of angular frequency 100 and 1000 rad s⁻¹ have the same
- If the focal length of a concave mirror is 50 cm, then where should the object
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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