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For photoelectric emission from certain metal the cut-off frequency is v. If radiation of frequency 2v impinges on the metal plate, the maximum possible velocity of the emitted electron will be (m is the electron mass)
Options
(a) √ hv / m
(b) √ 2hv / m
(c) 2 √hv / m
(d) √ hv / (2m)
Correct Answer:
√ 2hv / m
Explanation:
From photo-electric equation,
hv’ = hv + Kₘₐₓ …(i)
h.2v = hv + 1/2 mV²ₘₐₓ [ v’ = 2v ]
hv = 1/2 mV²ₘₐₓ ⇒ Vₘₐₓ = √ 2hv / m
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A body of mass 1.0 kg is falling with an acceleration of 10 ms⁻².
- A simple pendulum has a time period T₁ when on the earth’s surface and T₂ When taken
- Two particles of masses m₁ m₂ move with initial velocities u₁ and u₂
- The ratio of the radii or gyration of a circular disc to that of a circular ring
- Two sources P and Q produce notes of frequency 660 Hz each.
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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