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For photoelectric emission from certain metal the cut-off frequency is v. If radiation of frequency 2v impinges on the metal plate, the maximum possible velocity of the emitted electron will be (m is the electron mass)
Options
(a) √ hv / m
(b) √ 2hv / m
(c) 2 √hv / m
(d) √ hv / (2m)
Correct Answer:
√ 2hv / m
Explanation:
From photo-electric equation,
hv’ = hv + Kₘₐₓ …(i)
h.2v = hv + 1/2 mV²ₘₐₓ [ v’ = 2v ]
hv = 1/2 mV²ₘₐₓ ⇒ Vₘₐₓ = √ 2hv / m
Related Questions: - A light of wavelength 5000Å falls on a sensitive plate with photoelectric work
- Equal charge q each are placed at the vertices AQ and B of an equilateral triangle
- Angle of contact of a liquid with a solid depends on
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A light of wavelength 5000Å falls on a sensitive plate with photoelectric work
- Equal charge q each are placed at the vertices AQ and B of an equilateral triangle
- Angle of contact of a liquid with a solid depends on
- A ball moving with velocity 2 m/s collides head on with another stationary ball
- A coil of resistance 10 Ω and an inductance 5 H is connected to a 100 volt
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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