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For photoelectric emission from certain metal the cut-off frequency is v. If radiation of frequency 2v impinges on the metal plate, the maximum possible velocity of the emitted electron will be (m is the electron mass)
Options
(a) √ hv / m
(b) √ 2hv / m
(c) 2 √hv / m
(d) √ hv / (2m)
Correct Answer:
√ 2hv / m
Explanation:
From photo-electric equation,
hv’ = hv + Kₘₐₓ …(i)
h.2v = hv + 1/2 mV²ₘₐₓ [ v’ = 2v ]
hv = 1/2 mV²ₘₐₓ ⇒ Vₘₐₓ = √ 2hv / m
Related Questions: - A parallel beam of fast moving electrons is incident normally on a narrow slit.
- Two sources of sound placed close to each other are emitting progressive waves
- The dimensions of Planck’s constant is same as that of
- A car moving with a velocity of 36 km/hr crosses a siren of frequency 500 Hz.
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Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A parallel beam of fast moving electrons is incident normally on a narrow slit.
- Two sources of sound placed close to each other are emitting progressive waves
- The dimensions of Planck’s constant is same as that of
- A car moving with a velocity of 36 km/hr crosses a siren of frequency 500 Hz.
- A block of mass m moving at a velocity v collides with another block of mass 2m
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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