| ⇦ |
| ⇨ |
A light of wavelength 5000Å falls on a sensitive plate with photoelectric work function 1.90 eV. Kinetic energy of the emitted photoelectrons will be (given, h=6.62×10⁻³⁴ Js)
Options
(a) 0.1 eV
(b) 2 eV
(c) 0.58 eV
(d) 1.581 eV
Correct Answer:
0.58 eV
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - An object is placed 30 cm away from a convex lens of focal length 10 cm and a sharp
- The escape velocity from the earth’s surface is 11 kms⁻¹.A certain planet
- Van der waals,equation of state is(p+a/v²)(V-b)=nRT. The dimensions of a and b
- Light with an energy flux of 25×10⁴ Wm⁻² falls on a perfectly reflecting surface
- The kinetic energy of an electron in the first excited state is
Topics: Dual Nature of Matter and Radiation
(150)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An object is placed 30 cm away from a convex lens of focal length 10 cm and a sharp
- The escape velocity from the earth’s surface is 11 kms⁻¹.A certain planet
- Van der waals,equation of state is(p+a/v²)(V-b)=nRT. The dimensions of a and b
- Light with an energy flux of 25×10⁴ Wm⁻² falls on a perfectly reflecting surface
- The kinetic energy of an electron in the first excited state is
Topics: Dual Nature of Matter and Radiation (150)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply