For a simple pendulum performing simple harmonic motion, the time period

For A Simple Pendulum Performing Simple Harmonic Motion The Time Physics Question

For a simple pendulum performing simple harmonic motion, the time period is plotted against its length. The curve will be

Options

(a) straight line
(b) circle
(c) parabola
(d) ellipse

Correct Answer:

parabola

Explanation:

Time period of a simple pendulum performing simple harmonic motion is given by
T = 2π √(l/g) where l is the length of the pendulum
or, T² = 4π²l/g or, T² ∝ l
Graph between T and l is a parabola.

Related Questions:

  1. If the distance between the plates of two capacitor is increased then capacitance
  2. For a series L-C-R circuit, the rms values of voltage across various components
  3. The radius of curvature of the convex face of a plano-convex lens is 12 cm
  4. A particle moves in a straight line with a constant acceleration
  5. A particle with charge q is moving along a circle of radius R with unoform speed v.

Topics: Oscillations (58)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*