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For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is
Options
(a) (1/2)
(b) 1/√2
(c) 2
(d) √2
Correct Answer:
(1/2)
Explanation:
-GMm/R² + mω²R = 0
GMm/R² = mω²R
Kinetic Energy = 1/2Iω²
KE= 1/2mR²ω² = GMm/2R
Potential energy = -GMm/R
Therefore, Kinetic energy = |Potential energy|/2
Kinetic energy/|Potential energy| = 1/2.
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Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The two ends of a rod of length L and a uniform cross-sectional area
- A heavy nucleus at rest breaks into two fragments which fly off with velocities
- The manifestation of band structure in solids is due to
- An object is seen through a simple microscope of focal length 12 cm.
- An α-particle moves in a circular path of radius 0.83 cm in the presence of a magnetic
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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