| ⇦ |
| ⇨ |
Two thin long conductors seprated by a distance d carry currents I₁ and I₂ in the same direction. They exert a force F on each other. Now, the current in one of them is increased to two times and its direction is reversed. The distance is also increased to 3d. The new value of force between them is
Options
(a) (-2F)
(b) F/3
(c) (-2F/3)
(d) (-F/3)
Correct Answer:
(-2F/3)
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A heavy stone hanging from a massless string of length 15 m is projected
- The moderator in a reactor
- A coil of N turns and mean cross-sectional area A is rotating with uniform angular
- MA⁻¹T⁻² is the dimensional formula of
- If a mass of 20g having charge 3.0 mC moving with velocity 20ms⁻¹ enters a region
Topics: Magnetic Effects of Current and Magnetism
(167)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A heavy stone hanging from a massless string of length 15 m is projected
- The moderator in a reactor
- A coil of N turns and mean cross-sectional area A is rotating with uniform angular
- MA⁻¹T⁻² is the dimensional formula of
- If a mass of 20g having charge 3.0 mC moving with velocity 20ms⁻¹ enters a region
Topics: Magnetic Effects of Current and Magnetism (167)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply