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For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is
Options
(a) (1/2)
(b) 1/√2
(c) 2
(d) √2
Correct Answer:
(1/2)
Explanation:
-GMm/R² + mω²R = 0
GMm/R² = mω²R
Kinetic Energy = 1/2Iω²
KE= 1/2mR²ω² = GMm/2R
Potential energy = -GMm/R
Therefore, Kinetic energy = |Potential energy|/2
Kinetic energy/|Potential energy| = 1/2.
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If two electric bulbs have 40 W and 60 W ratings at 220 V, then the ratio
- A solid sylinder of mass 3 kg is rolling on a horizontal surface with velocity 4 ms⁻¹
- A heavy uniform chain lies on a horizontal top table.If the coefficient of friction
- A car moving with a speed of 50 kmh⁻¹ can be stopped by brakes after at least 6 m
- A long horizontal rod has a bead which can slide long its length
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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