| ⇦ | 
| ⇨ |
For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is
Options
(a) (1/2)
(b) 1/√2
(c) 2
(d) √2
Correct Answer:
(1/2)
Explanation:
-GMm/R² + mω²R = 0
GMm/R² = mω²R
Kinetic Energy = 1/2Iω²
KE= 1/2mR²ω² = GMm/2R
Potential energy = -GMm/R
Therefore, Kinetic energy = |Potential energy|/2
Kinetic energy/|Potential energy| = 1/2.
Related Questions: - In the middle of the depletion layer of a reverse-biased P-N junction, the
- Magnetism of a magnet is due to
- A small signal voltage V(t)=V₀ sin ωt is applied across an ideal capacitor C
- Two blocks of masses m₁=4 kg and m₂= 2kg are connected to the ends of a string
- The amount of heat energy required to raise the temperature of 1 g of Helium
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the middle of the depletion layer of a reverse-biased P-N junction, the
- Magnetism of a magnet is due to
- A small signal voltage V(t)=V₀ sin ωt is applied across an ideal capacitor C
- Two blocks of masses m₁=4 kg and m₂= 2kg are connected to the ends of a string
- The amount of heat energy required to raise the temperature of 1 g of Helium
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply