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Enthalpy of CH₄ + ¹/² O₂ → CH₃OH is negative. If enthalpy of combustion of CH₄ and CH₃OH are x and y respectively. Then which relation is correct
Options
(a) x > y
(b) x < y
(c) x = y
(d) x > y
Correct Answer:
x < y
Explanation:
CH₄ + 1/2 O₂ → CH₃OH, ΔH = x -y; Given ΔH = negative. hence, x-y < 0, or n < y.
Related Questions: - Which one of the following gives only one monochloro derivative
- The predominant intermolecular forces in HF is due to
- The oxidation state of sulpur in sodium tetrathionate (Na₂S₄O₆) is
- The electron was shown experimentally to have wave properties by
- The geometry of Ni(CO)₄ and Ni(PPh₃)₂Cl₂ are
Topics: Thermodynamics
(179)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Which one of the following gives only one monochloro derivative
- The predominant intermolecular forces in HF is due to
- The oxidation state of sulpur in sodium tetrathionate (Na₂S₄O₆) is
- The electron was shown experimentally to have wave properties by
- The geometry of Ni(CO)₄ and Ni(PPh₃)₂Cl₂ are
Topics: Thermodynamics (179)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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