| ⇦ | 
| ⇨ |
Electric potential at any point is V= -5x +3y + √(15) z. Then the magnitude of electric field is
Options
(a) 3 √2
(b) 4 √2
(c) 5 √2
(d) 7
Correct Answer:
7
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two resistors of 6Ω and 9Ω are connected in series to a 120 V source.
- Light with an energy flux of 25×10⁴ Wm⁻² falls on a perfectly reflecting surface
- An electron moves on a straight line path XY as shown. The abcd is a coil adjacent
- When a mass M is attached to the spring of force constant k,
- Two bulbs 40 watt and 60 watt and rated voltage 240 V are connected in series
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two resistors of 6Ω and 9Ω are connected in series to a 120 V source.
- Light with an energy flux of 25×10⁴ Wm⁻² falls on a perfectly reflecting surface
- An electron moves on a straight line path XY as shown. The abcd is a coil adjacent
- When a mass M is attached to the spring of force constant k,
- Two bulbs 40 watt and 60 watt and rated voltage 240 V are connected in series
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply