| ⇦ |
| ⇨ |
At what distance from the centre of earth, the value of acceleration due to gravity will be half that on the surface (R=radius of earth)
Options
(a) 2 R
(b) R
(c) 1.414 R
(d) 0.414 R
Correct Answer:
0.414 R
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - If rope of lift breaks suddenly, the tension exerted by the surface of the lift
- Find the right condition(s) for Fraunhofer diffraction due to a single slit.
- A particle of mass m executes simple harmonic motion with amplitude
- A stone tied to the end of a string of 1 m long is whirled in a horizontal circle
- An object is seen through a simple microscope of focal length 12 cm.
Topics: Gravitation
(63)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If rope of lift breaks suddenly, the tension exerted by the surface of the lift
- Find the right condition(s) for Fraunhofer diffraction due to a single slit.
- A particle of mass m executes simple harmonic motion with amplitude
- A stone tied to the end of a string of 1 m long is whirled in a horizontal circle
- An object is seen through a simple microscope of focal length 12 cm.
Topics: Gravitation (63)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

By using the formula g’/g=(R/R+h)^2 we can find the answer