| ⇦ | 
| ⇨ |
Electric potential at any point is V= -5x +3y + √(15) z. Then the magnitude of electric field is
Options
(a) 3 √2
(b) 4 √2
(c) 5 √2
(d) 7
Correct Answer:
7
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A particle moving in a straight line with uniform acceleration is observed
- Two electrons are separated by a distance of 1Å. What is the coulomb force between them?
- Two 220V – 100W bulbs are connected first in series and then in parallel.
- Which one of the following statements is not correct in case of a semiconductor?
- A ray of light is incident at an angle of incidence i, on one face of a prism
Topics: Electrostatics
(146)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle moving in a straight line with uniform acceleration is observed
- Two electrons are separated by a distance of 1Å. What is the coulomb force between them?
- Two 220V – 100W bulbs are connected first in series and then in parallel.
- Which one of the following statements is not correct in case of a semiconductor?
- A ray of light is incident at an angle of incidence i, on one face of a prism
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply