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At S.T.P the density of CCl₄ vapours in g/L will be nearest to
Options
(a) 6.87
(b) 3.42
(c) 10.26
(d) 4.57
Correct Answer:
6.87
Explanation:
Molecular Weight of CCl₄ = 35.5 + 12 x 4 = 154
1 mole CCl₄ vapour=154 g
According to Avogadro’s hypothesis we know that the molar volume of a gas at STP is 22.4 litres
= 154/22.4 = 6.87
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- Which is weakest acid
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Question Type: Memory (964)
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Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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