| ⇦ | 
| ⇨ |
At 10⁰C the value of the density of a fixed mass of an ideal gas divided by its pressure is x. At 110⁰ C this ratio is:
Options
(a) x
(b) (383 / 283) x
(c) (10 / 110) x
(d) (283 / 383) x
Correct Answer:
(283 / 383) x
Explanation:
Let the mass of the gas be m. AT fixed temperature and pressure, volume is fixed. Density of the gas, ρ = m / V
Now ρ / P = m / PV = M / nRT = x (By question)
xT = constant x₁T₁ = x₂T₂
x₂ = x₁T₁ / T₂ = (283 / 383) x
[T₁ = 283 K, T₂ = 383 K ]
Related Questions: - Two springs with spring constants K₁=1500 N/m and K₂=3000 N/m
- A liquid boils when its vapour pressure equals
- In a LCR series circuit, the potential difference between the terminals of the inductor
- A paramagnetic sample shows a net magnetisation of 0.8 Am⁻¹, when placed
- If the minimum energy of photons needed to produce photoelectrons is 3 eV,
Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two springs with spring constants K₁=1500 N/m and K₂=3000 N/m
- A liquid boils when its vapour pressure equals
- In a LCR series circuit, the potential difference between the terminals of the inductor
- A paramagnetic sample shows a net magnetisation of 0.8 Am⁻¹, when placed
- If the minimum energy of photons needed to produce photoelectrons is 3 eV,
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Very good one..
I saw same answer on other site as well but they were too lengthy.