| ⇦ |
| ⇨ |
At 10⁰C the value of the density of a fixed mass of an ideal gas divided by its pressure is x. At 110⁰ C this ratio is:
Options
(a) x
(b) (383 / 283) x
(c) (10 / 110) x
(d) (283 / 383) x
Correct Answer:
(283 / 383) x
Explanation:
Let the mass of the gas be m. AT fixed temperature and pressure, volume is fixed. Density of the gas, ρ = m / V
Now ρ / P = m / PV = M / nRT = x (By question)
xT = constant x₁T₁ = x₂T₂
x₂ = x₁T₁ / T₂ = (283 / 383) x
[T₁ = 283 K, T₂ = 383 K ]
Related Questions: - The ratio of minimum wavelengths of Lyman and Balmer series will be
- Eight drops of a liquid of density ρ and each of radius a are falling through air
- In P-N junction having depletion layer of thickness 10⁻⁶ m, the potential across
- In a series resonant LCR circuit, the voltage across R is 100 volts and R =1kΩ
- The barrier potential of a p-n junction depends on
Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ratio of minimum wavelengths of Lyman and Balmer series will be
- Eight drops of a liquid of density ρ and each of radius a are falling through air
- In P-N junction having depletion layer of thickness 10⁻⁶ m, the potential across
- In a series resonant LCR circuit, the voltage across R is 100 volts and R =1kΩ
- The barrier potential of a p-n junction depends on
Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Very good one..
I saw same answer on other site as well but they were too lengthy.