At 10⁰C the value of the density of a fixed mass of an ideal gas divided by its pressure

At 10c The Value Of The Density Of A Fixed Physics Question

At 10⁰C the value of the density of a fixed mass of an ideal gas divided by its pressure is x. At 110⁰ C this ratio is:

Options

(a) x
(b) (383 / 283) x
(c) (10 / 110) x
(d) (283 / 383) x

Correct Answer:

(283 / 383) x

Explanation:

Let the mass of the gas be m. AT fixed temperature and pressure, volume is fixed. Density of the gas, ρ = m / V
Now ρ / P = m / PV = M / nRT = x (By question)
xT = constant x₁T₁ = x₂T₂
x₂ = x₁T₁ / T₂ = (283 / 383) x
[T₁ = 283 K, T₂ = 383 K ]

Related Questions:

  1. Excitation energy of a hydrogen like ion, in its first excitation state, is 40.8 eV.
  2. Hard X-rays for the study of fractures in bones should have a minimum wavelength
  3. Two particles which are initially at rest, move towards each other
  4. A electric dipole is placed at an angle of 30⁰ to a non-uniform electric field.
  5. A fringe width of a certain interference pattern is β=0.002 cm. What is the distance

Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

1 Comment on At 10⁰C the value of the density of a fixed mass of an ideal gas divided by its pressure

Leave a Reply

Your email address will not be published.


*