⇦ | ![]() | ⇨ |
At 10⁰C the value of the density of a fixed mass of an ideal gas divided by its pressure is x. At 110⁰ C this ratio is:
Options
(a) x
(b) (383 / 283) x
(c) (10 / 110) x
(d) (283 / 383) x
Correct Answer:
(283 / 383) x
Explanation:
Let the mass of the gas be m. AT fixed temperature and pressure, volume is fixed. Density of the gas, ρ = m / V
Now ρ / P = m / PV = M / nRT = x (By question)
xT = constant x₁T₁ = x₂T₂
x₂ = x₁T₁ / T₂ = (283 / 383) x
[T₁ = 283 K, T₂ = 383 K ]
Related Questions:
- 24 cells of emf 1.5 V each having internal resistance of 1 ohm are connected
- The effective length of magnet is 31.4 cm and its pole strength is 0.8Am.
- A 70 kg man stands in contact against the inner wall of a hollow cylindrical drum
- A force acts on a 3.0 g particle in such a way that the position of the particle
- Which one of the following is not a unit of young’s modulus?
Topics: Behavior of Perfect Gas and Kinetic Theory
(34)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Very good one..
I saw same answer on other site as well but they were too lengthy.