At 10⁰C the value of the density of a fixed mass of an ideal gas divided by its pressure

At 10c The Value Of The Density Of A Fixed Physics Question

At 10⁰C the value of the density of a fixed mass of an ideal gas divided by its pressure is x. At 110⁰ C this ratio is:

Options

(a) x
(b) (383 / 283) x
(c) (10 / 110) x
(d) (283 / 383) x

Correct Answer:

(283 / 383) x

Explanation:

Let the mass of the gas be m. AT fixed temperature and pressure, volume is fixed. Density of the gas, ρ = m / V
Now ρ / P = m / PV = M / nRT = x (By question)
xT = constant x₁T₁ = x₂T₂
x₂ = x₁T₁ / T₂ = (283 / 383) x
[T₁ = 283 K, T₂ = 383 K ]

Related Questions:

  1. A wire carrying current I has the shape as shown in adjoining figure. Linear parts
  2. If L and C denote inductance and capacitance,then the dimensions of L-C are
  3. If a vector 2i+3j+8k is perpendicular to the vector 4j-4i+αk, then value of α is
  4. According to photon theory of light which of the following physical quantities,
  5. An inductor is connected to an a.c. source when compared to voltage,

Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

1 Comment on At 10⁰C the value of the density of a fixed mass of an ideal gas divided by its pressure

Leave a Reply

Your email address will not be published.


*