MENU

At 10⁰C the value of the density of a fixed mass of an ideal gas divided by its pressure

At 10c The Value Of The Density Of A Fixed Physics Question

At 10⁰C the value of the density of a fixed mass of an ideal gas divided by its pressure is x. At 110⁰ C this ratio is:

Options

(a) x
(b) (383 / 283) x
(c) (10 / 110) x
(d) (283 / 383) x

Correct Answer:

(283 / 383) x

Explanation:

Let the mass of the gas be m. AT fixed temperature and pressure, volume is fixed. Density of the gas, ρ = m / V
Now ρ / P = m / PV = M / nRT = x (By question)
xT = constant x₁T₁ = x₂T₂
x₂ = x₁T₁ / T₂ = (283 / 383) x
[T₁ = 283 K, T₂ = 383 K ]

Related Questions:

  1. The amplitude of S.H.M. y=2 (sin 5πt+√2 cos 5πt) is
  2. The induced emf in a coil of 10 H inductance in which current varies
  3. If force(F), Velocity(V) and time(T) are taken as fundamental units, then the dimensions
  4. A nucleus at rest splits into two nuclear parts having radii in the ratio 1:2.
  5. In the given figure, a diode D is connected to an external resistance R=100 Ω

Topics: Behavior of Perfect Gas and Kinetic Theory (34)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

1 Comment on At 10⁰C the value of the density of a fixed mass of an ideal gas divided by its pressure

Leave a Reply

Your email address will not be published.


*