Assuming fully decomposed, the volume of CO₂ released at STP on heating 9.85g

⇦

⇨

Assuming fully decomposed, the volume of CO₂ released at STP on heating 9.85 g of BaCO₃(Atomic mass Ba=137) will be

Options

(a) 2.24 L
(b) 4.96 L
(c) 1.12L
(d) 0.84L

Correct Answer:

1.12L

Explanation:

BaCO₃ → BaO+ CO₂
Atomic Mass of Ba=137
Atomic Mass of C=12
Atomic Mass of O=16
Molecular Mass of BaCO₃ = 137 + 12 + (16*3) = 197
197 gm of BaCO₃ released carbondioxide = 22.4 litre at STP
1 gm of BaCO₃ released carbondioxide = 22.4/197 litre
9.85 gm of BaCO₃ released carbondioxide = 22.4/197 x 9.85 = 1.12 litre

Related Questions:

1. Which of the following order is wrong?
2. The volume of 3.0 N-H₂O₂ strength is
3. The ore horn silver corresponds to
4. Allyl isocyanide has
5. Among the following the most reactive towards alcoholic KOH is

Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends