| ⇦ |
| ⇨ |
Angle of minimum deviation for a prism of reractive index 1.5 equal to the angle of prism of given prism. Then, the angle of prism is …….
(sin 48⁰36′ =0.75)
Options
(a) 80⁰
(b) 41⁰24′
(c) 60⁰
(d) 82⁰48′
Correct Answer:
82⁰48′
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two cities are 150 km apart. Electric power is sent from one city to another city
- In a uniform circular motion,
- A small angled prism of refractive index 1.4 is combined with another small angled prism
- Huygen’s wave theory allows us to know
- Which of the following transitions will have highest emission wavelength?
Topics: Ray Optics
(94)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two cities are 150 km apart. Electric power is sent from one city to another city
- In a uniform circular motion,
- A small angled prism of refractive index 1.4 is combined with another small angled prism
- Huygen’s wave theory allows us to know
- Which of the following transitions will have highest emission wavelength?
Topics: Ray Optics (94)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply