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An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A planet moving along an elliptical orbit is closest to the sun at a distance of r₁
- The kinetic energy of α-particle emitted in the α-dacay of ₈₈Ra²²⁶ is
- A certain number of spherical dropes of a liquid of radius r coalesce to form a single
- What determines the nature of the path followed by the particle?
- The earth is assumed to be a sphere of radius R. A platform is arranged at a height R
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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