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An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A hollow sphere of radius 0.1m has a charge of 5×10⁻⁸C. The potential
- In which of the follows decays, the element does not change?
- A simple pendulum is suspended from the ceiling of a lift. When the lift is at rest
- A Gaussian surface in the cylinder of cross-section πa² and length L is immersed
- A tangent galvanometer has a coil of 50 turns and a radius of 20 cm. The horizontal
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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