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An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Photons with energy 5eV are incident on a cathode C in a photoelectric cell.
- The coherence of two light sources means that the light waves emitted have
- A closely wound solenoid of 2000 turns and area of cross-section 1.5 x 10⁻⁴ m² carries
- A astronomical telescope has objective and eye-piece of focal lengths
- when a magnetic field is applied on a stationary electron, then it
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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