| ⇦ | 
| ⇨ |
An organic compound containing C, H, N gave the following analysis: C=40%; H=13.33%; N=46.67%. Its empirical formula would be
Options
(a) C₂H₇N₂
(b) CH₅N
(c) CH₄N
(d) C₂H₇N
Correct Answer:
CH₄N
Explanation:
At wt of C = 12
Rel Number for C = 40/12 = 3.66
Ratio for C = 3.66/3.33 = 1.09
At wt of H = 1
Rel Number for H = 13.33/1 = 13.33
Ratio for H = 13.33/3.33 = 4
At wt of N = 14
Rel Number for N = 46.67/14 = 3.33
Ratio for N = 3.33/3.33 = 1
Hence empirical formula is CH₄N
Related Questions: - 75% of a first order reaction was completed in 32min.When was 50% of the reaction
- Which of the following is ferroelectric compound
- The oxidation number of As in H₂AsO₄⁻ is
- Treatment of a mixture of CH₃Cl and C₂H₅Cl with sodium in dry ether can generat
- Which ion is detected by Nessler’s reagent
Question Type: Memory
(964)
Difficulty Level: Easy
(1008)
Topics: Basic Concepts of Chemistry
(94)
Subject: Chemistry
(2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- 75% of a first order reaction was completed in 32min.When was 50% of the reaction
- Which of the following is ferroelectric compound
- The oxidation number of As in H₂AsO₄⁻ is
- Treatment of a mixture of CH₃Cl and C₂H₅Cl with sodium in dry ether can generat
- Which ion is detected by Nessler’s reagent
Question Type: Memory (964)
Difficulty Level: Easy (1008)
Topics: Basic Concepts of Chemistry (94)
Subject: Chemistry (2512)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply