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An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A Gaussian surface in the cylinder of cross-section πa² and length L is immersed
- A hollow metal sphere of radius 10 cm is charged such that the potential on its surface
- The average power dissipated in a pure inductor is
- Two capacitors having capacitances C₁ and C₂ are charged with 120V and 200V batteries
- A wire of a certain material is stretched slowly by ten percent. Its new resistance
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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