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An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- An A.C source is rated at 220 V, 50 Hz. The time taken for voltage to change
- A 2 kg mass starts from rest on an inclined smooth surface with inclination
- A monoatomic gas at a pressure P, having a volume V expands isothermally
- A coil of resistance 10 Ω and an inductance 5 H is connected to a 100 volt
- A fringe width of a certain interference pattern is β=0.002 cm. What is the distance
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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