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An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A lead bullet of 10 gm travelling at 300 m/s strikes against a block
- A 0.01 H inductor and √3 πΩ resistance are connected in series
- Periodic time of a satellite revolving above Earth’s surface at a height equal to R,
- A silver wire of radius 0.1 cm carries a current of 2A. If the charge density in silver
- A solenoid has length 0.4 cm, radius 1 cm and 400 turns of wire. If a current
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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