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An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by (dv/dt)= -2.5√v, where v is the instantaneous speed.The time taken by the object ,to come to rest would be
Options
(a) 2 s
(b) 4 s
(c) 8 s
(d) 1 s
Correct Answer:
2 s
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A parallel plate air capacitor has capacity C, distance of seperation between plate
- Pure Si at 300 k has equal electrons (nₑ) and hole (nh) concentrations
- The condition for obtaining secondary maxima in the diffraction pattern
- If the sodium light in Young’s double slit experiment is replaced by red light
- Two particles P and Q start from origin and execute simple harmonic motion along X-axis
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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