| ⇦ | 
| ⇨ |
An electron in the hydrogen atom jumps from excited state n to the ground state. The wavelength so emitted illuminates a photosensitive material having work function 2.75 eV. If the stopping potential of the photoelectron is 10 V, the value of n is
Options
(a) 3
(b) 4
(c) 5
(d) 2
Correct Answer:
4
Explanation:
KEₘₐₓ = 10 eV ? = 2.75 eV
Total incident energy
E = ? + KEₘₐₓ = 12.75 eV
Energy is released when electron jumps from the excited state n to the ground state.
E₄ – E₁ = {-0.85 – (-13.6) eV}
= 12.75 eV value of n = 4.
Related Questions: - If alpha, beta and gamma rays carry same momentum, which has the longest
- When a sound wave of wavelength λ is propagating in a medium,
- A ball rolls off the top of stair way with a horizontal velocity of magnitude 1.8 m/s
- Dimensions of resistance in an electrical circuit, in terms of dimension of mass M,
- In the given figure, a diode D is connected to an external resistance R=100 Ω
Topics: Atoms and Nuclei
(136)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If alpha, beta and gamma rays carry same momentum, which has the longest
- When a sound wave of wavelength λ is propagating in a medium,
- A ball rolls off the top of stair way with a horizontal velocity of magnitude 1.8 m/s
- Dimensions of resistance in an electrical circuit, in terms of dimension of mass M,
- In the given figure, a diode D is connected to an external resistance R=100 Ω
Topics: Atoms and Nuclei (136)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply