An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into

⇦

⇨

An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into a dielectric medium with relative permittivity ε = 4.0. Then

Options

(a) wavelength is doubled and frequency is unchanged
(b) wavelength is doubled and frequency becomes half
(c) wavelength is halved and frequency remains unchanged
(d) wavelength and frequency both remain unchanged

Correct Answer:

wavelength is halved and frequency remains unchanged

Explanation:

Given : frequency f = 2 MHz, relative permitivity εᵣ = 4
For formula,
velocity v = c / √εᵣ = c / 2
λ’ = λ / 2
[since frequency remains unchanged ]

Related Questions:

1. The electric field at a distance 3R / 2 from the centre of a charged conducting
2. A wheel is rotating at 900 rpm about its axis.When the power is cut-off it
3. The vector sum of two forces is perpendicular to their vector difference. In that case,
4. An object moving with a speed of 6.25 m/s, is deaccelerated at a rate given by
5. A series combination of resistor (R), capacitor (C), is connected to an AC source

Topics: Electromagnetic Waves (28)
Subject: Physics (2479)

---

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

---

Share this page with your friends