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An electromagnetic wave of frequency v = 3.0 MHz passes from vacuum into a dielectric medium with relative permittivity ε = 4.0. Then
Options
(a) wavelength is doubled and frequency is unchanged
(b) wavelength is doubled and frequency becomes half
(c) wavelength is halved and frequency remains unchanged
(d) wavelength and frequency both remain unchanged
Correct Answer:
wavelength is halved and frequency remains unchanged
Explanation:
Given : frequency f = 2 MHz, relative permitivity εᵣ = 4
For formula,
velocity v = c / √εᵣ = c / 2
λ’ = λ / 2
[since frequency remains unchanged ]
Related Questions: - The two ends of a rod of length L and a uniform cross-sectional area
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Topics: Electromagnetic Waves
(28)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The two ends of a rod of length L and a uniform cross-sectional area
- A ray of light travelling in a transparent medium of refractive index µ, falls on surface
- A particle of mass m, charge Q and kinetic enery T enters a transverse
- A particle doing SHM has amplitude=4 cm and time period = 12 sec. The ratio between times
- The work function of metals is in the range of 2 eV to 5 eV.
Topics: Electromagnetic Waves (28)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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