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An electric lamp is connected to 220 V, 50 Hz supply. Then the peak voltge is
Options
(a) 210 V
(b) 211 V
(c) 311 V
(d) 320 V
Correct Answer:
311 V
Explanation:
Measurement of A.C voltage gives the rms values.
V(rms) = 220 V
Peak value Vm = V(rms) √2 = √2 (220 V) = 311 V.
Related Questions: - The current in a self-inductance L=40 mH is to be increased uniformly from 1A to 11 A
- A charged particle of mass m and charge q moves along a circular path of radius
- The current gain of a transistor in common base configuration is 0.96.
- A dynamo converts
- Find out the e.m.f. produced when the current changes from 0 to 1 A in 10 sec.
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The current in a self-inductance L=40 mH is to be increased uniformly from 1A to 11 A
- A charged particle of mass m and charge q moves along a circular path of radius
- The current gain of a transistor in common base configuration is 0.96.
- A dynamo converts
- Find out the e.m.f. produced when the current changes from 0 to 1 A in 10 sec.
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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