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An electric lamp is connected to 220 V, 50 Hz supply. Then the peak voltge is
Options
(a) 210 V
(b) 211 V
(c) 311 V
(d) 320 V
Correct Answer:
311 V
Explanation:
Measurement of A.C voltage gives the rms values.
V(rms) = 220 V
Peak value Vm = V(rms) √2 = √2 (220 V) = 311 V.
Related Questions: - The kirchoff’s first law (∑i=0) and second law (∑iR=∑E), where the symbols
- A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
- In an A.C circuit of capacitance the current from potential is
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The kirchoff’s first law (∑i=0) and second law (∑iR=∑E), where the symbols
- A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
- In an A.C circuit of capacitance the current from potential is
- A beam of light of wavelength 600 nm from a distant source falls
- In the equation y=asin(?t+kx),the dimensionals formula of ? is
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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