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An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor of capacitance 2 μF. The impedence of the circuit is
Options
(a) π/5000
(b) 1000/π
(c) 500π
(d) 5000/π
Correct Answer:
5000/π
Explanation:
Impedance of a capacitor is Xc = 1 / ωC
Xc = 1 / 2πfC = 1 / (2π × 50 × 2 × 10⁻⁶) = 5000 / π
Related Questions: - According to photon theory of light which of the following physical quantities,
- A nucleus ᴢXᴬ emits an α- particle with velocity v. The recoil speed of the daughter
- The electromagnetic theory of light failed to explain
- An electric dipole is placed at an angle 30°with an electric field intensity 2×10⁵N/C.
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Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- According to photon theory of light which of the following physical quantities,
- A nucleus ᴢXᴬ emits an α- particle with velocity v. The recoil speed of the daughter
- The electromagnetic theory of light failed to explain
- An electric dipole is placed at an angle 30°with an electric field intensity 2×10⁵N/C.
- A body initially at rest is moving with uniform acceleration a m/s²
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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