| ⇦ |
| ⇨ |
An alternating voltage e=200s in100t is applied to a series combination of R= 30Ω and an inductor of 400 mH. The power factor of the circuit is
Options
(a) 0.01
(b) 0.05
(c) 0.042
(d) 0.6
Correct Answer:
0.6
Explanation:
Xʟ = Lω = 0.4 × 100 = 40
R = 30 Ω
.·. Power factor, cos ɸ = R / √(R² × Xʟ²) = 30 / √(R² × Xʟ²) = 30 / √(30² × 40²) = 0.6
Related Questions: - A wire in the form of a circular loop of one turn, carrying a current, produces
- The distance travelled by a particle starting from rest and moving with an acceleration
- Find the right condition(s) for Fraunhofer diffraction due to a single slit.
- The potential energy of a simple harmonic oscillator when the particle is half way
- The excess pressure inside one soap bubble is three times that inside a second soap bubble
Topics: Alternating Current
(96)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A wire in the form of a circular loop of one turn, carrying a current, produces
- The distance travelled by a particle starting from rest and moving with an acceleration
- Find the right condition(s) for Fraunhofer diffraction due to a single slit.
- The potential energy of a simple harmonic oscillator when the particle is half way
- The excess pressure inside one soap bubble is three times that inside a second soap bubble
Topics: Alternating Current (96)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply