| ⇦ | 
| ⇨ |
The distance travelled by a particle starting from rest and moving with an acceleration (4/3)ms⁻², in the 3rd second is
Options
(a) 6 m
(b) 4 m
(c) 10/3 m
(d) 19/3 m
Correct Answer:
10/3 m
Explanation:
Distance travelled in the nth second is given by tₙ = u + a/2 (2n – 1)
put u= 0, a= 4/3 ms⁻², n= 3
d= 0 + 4/ 3×2 (2 x 3 – 1) = 4/6 x 5 = 10/ 3 m
Related Questions: - Two lines of force due to a bar magnet
- A generator at a utility company produces 100 A of current at 4000 V. The voltage
- A sphere of 4cm radius is suspended with in a hollow sphere of 6cm radius. If the inner
- Avalanche breakdown is due to
- When a beam of light is used to determine the position of an object,
Question Type: Apply
(15)
Difficulty Level: Easy
(1008)
Topics: Motion in Straight Line
(93)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two lines of force due to a bar magnet
- A generator at a utility company produces 100 A of current at 4000 V. The voltage
- A sphere of 4cm radius is suspended with in a hollow sphere of 6cm radius. If the inner
- Avalanche breakdown is due to
- When a beam of light is used to determine the position of an object,
Question Type: Apply (15)
Difficulty Level: Easy (1008)
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply