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The distance travelled by a particle starting from rest and moving with an acceleration (4/3)ms⁻², in the 3rd second is
Options
(a) 6 m
(b) 4 m
(c) 10/3 m
(d) 19/3 m
Correct Answer:
10/3 m
Explanation:
Distance travelled in the nth second is given by tₙ = u + a/2 (2n – 1)
put u= 0, a= 4/3 ms⁻², n= 3
d= 0 + 4/ 3×2 (2 x 3 – 1) = 4/6 x 5 = 10/ 3 m
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Question Type: Apply
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Difficulty Level: Easy
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Topics: Motion in Straight Line
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A train moving at a speed of 220 ms⁻¹ towards a stationary object
- The moment of inertia of a semicircular ring about the centre is
- The unit of permitivity of free space, ε₀ is
- A sound absorber attenuates the sound level by 20 dB. The intensity decreases
- A transformer of 100% efficiency has 200 turns in the primary coil and 40000 turns
Question Type: Apply (15)
Difficulty Level: Easy (1008)
Topics: Motion in Straight Line (93)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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