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The distance travelled by a particle starting from rest and moving with an acceleration (4/3)ms⁻², in the 3rd second is
Options
(a) 6 m
(b) 4 m
(c) 10/3 m
(d) 19/3 m
Correct Answer:
10/3 m
Explanation:
Distance travelled in the nth second is given by tₙ = u + a/2 (2n – 1)
put u= 0, a= 4/3 ms⁻², n= 3
d= 0 + 4/ 3×2 (2 x 3 – 1) = 4/6 x 5 = 10/ 3 m
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A mixture consists of two radioactive materials A₁ and A₂ with half lives of 20s
- In the equation y=asin(?t+kx),the dimensionals formula of ? is
- A 1 kg particle strikes a wall with velocity 1 m/s at an angle 30° and reflects
- A sound source is moving towards a stationary listener with 1/10th of the speed
- A metal bar of length L and area of cross-section A is clamped between two rigid
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Difficulty Level: Easy (1008)
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Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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