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An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - Two resistances 3Ω and 6Ω are connected in parallel
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two resistances 3Ω and 6Ω are connected in parallel
- A body of mass 3 kg is under a constant force which cause a displacement
- A beam of electron passes undeflected through mutually perpendicular
- Photons of energy 6 eV are incident on a metal surface whose work function is 4 eV.
- Which of the following atoms has the lowest ionisation potential?
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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