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An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- For a cubic crystal structure which one of the following relations
- If doubly ionised lithium atom is hydrogen like with atomic number 3, the wavelength
- For transistor action (1) Base, emitter and collector regions should have similar size
- Which one of the following statements is not correct in case of a semiconductor?
- A circular disc of radius R and thickness R/6 has moment of inertia I about an axis
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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