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An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- One coolie takes 1 minute to raise a suitcase through a height of 2 m
- A body of mass 0.25 kg is projected with muzzle velocity 100 m/s from a tank
- When npn transistor is used as an amplifier
- In atom bomb, the reaction which occurs is
- If the band gap between valence band and conduction band in a material is 5.0 eV,
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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