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An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If μᵥ=1.5230 and μʀ=15.145, then dispersive power of crown glass is
- At which place, Earth’s magnetism becomes horizontal
- Three cells, each of e.m.f 1.5 V and internal resistance 1 ohm are connected in parallel
- A particle moves a distance x in time but according to equation x=(t+5)⁻¹
- Two bodies of mass 0.25 kg each moving towards each other with velocity
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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