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An α-particle of energy 5 MeV is scattered through 180⁰ by a fixed uranium nucleus. The distance of the closest approach is of the order of
Options
(a) 1Å
(b) 10⁻¹⁰ cm
(c) 10⁻¹² cm
(d) 10⁻¹⁵ cm
Correct Answer:
10⁻¹² cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Radioactivity
(83)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If a carnot engine is working with source temperature at 227⁰C and sink
- A person cannot see the objects clearly placed at a distance more than 40 cm
- In India, electricity is supplied for domestic use at 200V. It is supplied at 110 V
- The voltage of an a.c.supply varies with time (t) as V=120 sin 100 πt the maximum voltage
- If Q, E and W denote respectively the heat added, change in internal energy
Topics: Radioactivity (83)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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