| ⇦ |
| ⇨ |
A Zenor diode has a contact potential of 1 V in the absence of biasing. It undergoes Zenor breakdown for an electric field of 10⁶ V/m at the depletion region of p-n junction. If the width of the depletion region is 2.5 μm, what should be the reverse biased potential for the Zenor breakdown to occur?
Options
(a) 3.5 V
(b) 2.5 V
(c) 1.5 V
(d) 0.5 V
Correct Answer:
2.5 V
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In thermodynamics processes which of the following statements is not true?
- Core of electromagnets are made of ferromagnetic material which has
- A light emitting diode(LED) has a voltage drop of 2 volt across it
- A capacitor is used to store 24 watt hour of energy at 1200 volt.
- A student performs an experiment to determine the Young’s modulus of a wire
Topics: Electronic Devices
(124)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In thermodynamics processes which of the following statements is not true?
- Core of electromagnets are made of ferromagnetic material which has
- A light emitting diode(LED) has a voltage drop of 2 volt across it
- A capacitor is used to store 24 watt hour of energy at 1200 volt.
- A student performs an experiment to determine the Young’s modulus of a wire
Topics: Electronic Devices (124)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

V=E*d
E=10^6 v/m
d=2.5 μm
Therefor V=2.5