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A tuning fork of frequency x produces 4 beats with a source of 256 Hz and 8 beats with another source of 268 Hz. Then x equals to
Options
(a) 256 Hz
(b) 260 Hz
(c) 264 Hz
(d) 268 Hz
Correct Answer:
260 Hz
Explanation:
Frequency of tuning fork be x.
.·. x = 256 ± 4 = 260 or 252 Hz.
x = 268 ± 8 = 276 Hz or 260 Hz
.·. x =260 Hz.
Related Questions: - Four point masses, each of value m, are placed at the corners of a square ABCD
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Four point masses, each of value m, are placed at the corners of a square ABCD
- A single slit Fraunhogger diffraction pattern is formed with white light.
- Two discs of moment of inertia l₁ and I₂ and angular speeds
- An electron moving in a circular orbit of radius r makes n rotations per second.
- In a tangent galvanometer, a current of 0.1 A produces a deflection of 30⁰.
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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