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A tuning fork of frequency x produces 4 beats with a source of 256 Hz and 8 beats with another source of 268 Hz. Then x equals to
Options
(a) 256 Hz
(b) 260 Hz
(c) 264 Hz
(d) 268 Hz
Correct Answer:
260 Hz
Explanation:
Frequency of tuning fork be x.
.·. x = 256 ± 4 = 260 or 252 Hz.
x = 268 ± 8 = 276 Hz or 260 Hz
.·. x =260 Hz.
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Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The ionisation energy of an electron in the ground state of helium atom is 24.6 eV.
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- Reactance of a capacitor of capacitance C µF for A.C freqency (400 / π) Hz is 25 ohm
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Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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