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A tuning fork of frequency x produces 4 beats with a source of 256 Hz and 8 beats with another source of 268 Hz. Then x equals to
Options
(a) 256 Hz
(b) 260 Hz
(c) 264 Hz
(d) 268 Hz
Correct Answer:
260 Hz
Explanation:
Frequency of tuning fork be x.
.·. x = 256 ± 4 = 260 or 252 Hz.
x = 268 ± 8 = 276 Hz or 260 Hz
.·. x =260 Hz.
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Two tuning forks are sounded together and produce 2 beats per second.
- In L-C-R series circuit, an alternating emf e and current i are given by the equations
- Two metal spheres of radii 0.01m and 0.02m are given a charge of 15mC and 45mC
- A cricketer catches a ball of mass 150 g in 0.1 sec moving with speed 20 m/s
- An air core coil and an electric bulb are connected in series with an AC source.
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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