| ⇦ | 
| ⇨ |
A beam of light contains two wavelengths 6500Å and 5200Å. They form interference fringes in Young’s double slit experiment. What is the least distance (approx) from central maximum, where the bright fringes due to both wavelength coincide? The distance between the slits is 2 mm and the distance of screen is 120 cm.
Options
(a) 0.16 cm
(b) 0.32 cm
(c) 0.48 cm
(d) 1.92 cm
Correct Answer:
0.16 cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - The sodium nucleus ₁₁Na²³ contains
- A wire mesh consisting of very small squares is viewed at a distance
- Find out the angle of projection, if range is 4 times of maximum height
- A thermocouple is made from two metals, antimony and bismuth. If one junction
- Oil spreads over the surface of water where as water does not spread
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The sodium nucleus ₁₁Na²³ contains
- A wire mesh consisting of very small squares is viewed at a distance
- Find out the angle of projection, if range is 4 times of maximum height
- A thermocouple is made from two metals, antimony and bismuth. If one junction
- Oil spreads over the surface of water where as water does not spread
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply