| ⇦ |
| ⇨ |
A beam of light contains two wavelengths 6500Å and 5200Å. They form interference fringes in Young’s double slit experiment. What is the least distance (approx) from central maximum, where the bright fringes due to both wavelength coincide? The distance between the slits is 2 mm and the distance of screen is 120 cm.
Options
(a) 0.16 cm
(b) 0.32 cm
(c) 0.48 cm
(d) 1.92 cm
Correct Answer:
0.16 cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A block is moving up an inclined plane of inclination 60° with velocity of 20 ms⁻¹
- The density of ice is 0.9 g/cc and that of sea water is 1.1 g/cc
- α- particles, β – particles and γ – rays are all having same energy.
- The following four wires are made of the same material. Which of these will have
- If the terminal speed of a sphere of gold (density=19.5 kg/m³) is 0.2 m/s
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A block is moving up an inclined plane of inclination 60° with velocity of 20 ms⁻¹
- The density of ice is 0.9 g/cc and that of sea water is 1.1 g/cc
- α- particles, β – particles and γ – rays are all having same energy.
- The following four wires are made of the same material. Which of these will have
- If the terminal speed of a sphere of gold (density=19.5 kg/m³) is 0.2 m/s
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply