| ⇦ | 
| ⇨ |
A beam of light contains two wavelengths 6500Å and 5200Å. They form interference fringes in Young’s double slit experiment. What is the least distance (approx) from central maximum, where the bright fringes due to both wavelength coincide? The distance between the slits is 2 mm and the distance of screen is 120 cm.
Options
(a) 0.16 cm
(b) 0.32 cm
(c) 0.48 cm
(d) 1.92 cm
Correct Answer:
0.16 cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - A particle falls towards earth from infinity. Its velocity on reaching the earth
- A p-n-p transistor is used in common emitter mode in an amplifier circuit.
- Length of a string tied to two rigid supports is 40 cm. Maximum length
- Two capacitors having capacitances C₁ and C₂ are charged with 120V and 200V batteries
- A particle of unit mass undergoes one-dimensional motion such that its velocity varies
Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- A particle falls towards earth from infinity. Its velocity on reaching the earth
- A p-n-p transistor is used in common emitter mode in an amplifier circuit.
- Length of a string tied to two rigid supports is 40 cm. Maximum length
- Two capacitors having capacitances C₁ and C₂ are charged with 120V and 200V batteries
- A particle of unit mass undergoes one-dimensional motion such that its velocity varies
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply