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A beam of light contains two wavelengths 6500Å and 5200Å. They form interference fringes in Young’s double slit experiment. What is the least distance (approx) from central maximum, where the bright fringes due to both wavelength coincide? The distance between the slits is 2 mm and the distance of screen is 120 cm.
Options
(a) 0.16 cm
(b) 0.32 cm
(c) 0.48 cm
(d) 1.92 cm
Correct Answer:
0.16 cm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Wave Optics
(101)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- From a disc of radius R, a concentric circular portion of radius r is cut-out so
- The 6563 Å line emitted by hydrogen atom in a star is found to be red shifted by 5Å
- The work function for metals A,B abd C are respectively 1.92 eV,2.0 eV and 5 eV.
- A metal rod of length l cuts across a uniform magnetic field B with a velocity v.
- If the distance between the plates of two capacitor is increased then capacitance
Topics: Wave Optics (101)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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