A tuning fork of frequency 512 Hz makes 4 beats per second with the vibrating string

A Tuning Fork Of Frequency 512 Hz Makes 4 Beats Physics Question

A tuning fork of frequency 512 Hz makes 4 beats per second with the vibrating string of a piano. The beat frequency decreases to 2 beats per sec when the tension in the piano string is slightly increased. The frequency of the piano string before increasing the tension was

Options

(a) 510 Hz
(b) 514 Hz
(c) 516 Hz
(d) 508 Hz

Correct Answer:

508 Hz

Explanation:

The frequency of the piano string = 512+-4 = 516 or 508. When the tension is increased, beat frequency decreases to 2, it means that frequency of othe string is 508 as frequency of string increases with tension.

Related Questions:

  1. An electric lamp is connected to 220 V, 50 Hz supply. Then the peak voltge is
  2. An alternating voltage of 220 V, 50 Hz frequency is applied across a capacitor
  3. A certain number of spherical dropes of a liquid of radius r coalesce to form a single
  4. An electric kettle takes 4A current at 220 V. How much time will it take to boil 1 kg
  5. If longitudinal strain for a wire is 0.03 and its poisson’s ratio is 0.5

Topics: Waves (80)
Subject: Physics (2479)

Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score

18000+ students are using NEETLab to improve their score. What about you?

Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.

NEETLab Mobile App

Share this page with your friends

Be the first to comment

Leave a Reply

Your email address will not be published.


*