| ⇦ | 
| ⇨ |
A tuning fork of frequency 512 Hz makes 4 beats per second with the vibrating string of a piano. The beat frequency decreases to 2 beats per sec when the tension in the piano string is slightly increased. The frequency of the piano string before increasing the tension was
Options
(a) 510 Hz
(b) 514 Hz
(c) 516 Hz
(d) 508 Hz
Correct Answer:
508 Hz
Explanation:
The frequency of the piano string = 512+-4 = 516 or 508. When the tension is increased, beat frequency decreases to 2, it means that frequency of othe string is 508 as frequency of string increases with tension.
Related Questions: - In a region, the potential is represented by V(x,y,z)=6x-8xy-8y+6yz, where V
- A uranium nucleus ₉₂ U ²³⁸ emits an α-particle and a β-particle in succession.
- Two blocks of masses m₁=4 kg and m₂= 2kg are connected to the ends of a string
- In the reaction ₉₂U²³⁴→₈₇Y²²², how many α-particle and β-particles are emitted
- Three fourth of the active material decays in a radioactive sample in 3/4 sec
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In a region, the potential is represented by V(x,y,z)=6x-8xy-8y+6yz, where V
- A uranium nucleus ₉₂ U ²³⁸ emits an α-particle and a β-particle in succession.
- Two blocks of masses m₁=4 kg and m₂= 2kg are connected to the ends of a string
- In the reaction ₉₂U²³⁴→₈₇Y²²², how many α-particle and β-particles are emitted
- Three fourth of the active material decays in a radioactive sample in 3/4 sec
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply