⇦ | ⇨ |
A tuning fork frequency 512 Hz is vibrated with a sonometer wire and 6 beats per second are heard. The beat frequency reduces if the tension in the string is slightly increased. The original frequency of vibration of the string is
Options
(a) 506 Hz
(b) 512 Hz
(c) 518 Hz
(d) 524 Hz
Correct Answer:
518 Hz
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
Related Questions: - In the half wave rectifier circuit operating from 50 Hz mains frequency,
- The angle between the vectors (i+j) and (j+k) is
- A student performs an experiment to determine the Young’s modulus of a wire
- Figure below shows two paths that may be taken by a gas to go from a state A
- The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- In the half wave rectifier circuit operating from 50 Hz mains frequency,
- The angle between the vectors (i+j) and (j+k) is
- A student performs an experiment to determine the Young’s modulus of a wire
- Figure below shows two paths that may be taken by a gas to go from a state A
- The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends
Leave a Reply