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A tuning fork of frequency x produces 4 beats with a source of 256 Hz and 8 beats with another source of 268 Hz. Then x equals to
Options
(a) 256 Hz
(b) 260 Hz
(c) 264 Hz
(d) 268 Hz
Correct Answer:
260 Hz
Explanation:
Frequency of tuning fork be x.
.·. x = 256 ± 4 = 260 or 252 Hz.
x = 268 ± 8 = 276 Hz or 260 Hz
.·. x =260 Hz.
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Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- Three objects A,B and C are kept in a straight line on a frictionless horizontal surface
- In Young’s experiment, the ratio of maximum to minimum intensities of the fringe
- An electron in the hydrogen atom jumps from excited state n to the ground state
- In Young’s double slit interference experiment, using two coherent waves
- A disc of radius 0.1 m is rotating with a frequency 10 rev/sec in a normal magnetic
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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