| ⇦ |
| ⇨ |
A tuning fork of frequency x produces 4 beats with a source of 256 Hz and 8 beats with another source of 268 Hz. Then x equals to
Options
(a) 256 Hz
(b) 260 Hz
(c) 264 Hz
(d) 268 Hz
Correct Answer:
260 Hz
Explanation:
Frequency of tuning fork be x.
.·. x = 256 ± 4 = 260 or 252 Hz.
x = 268 ± 8 = 276 Hz or 260 Hz
.·. x =260 Hz.
Related Questions: - The pair of quantities having same dimensions is
- An aicraft executes a horizontal loop of radius 1 km with a speed of 900 kmh⁻¹
- The S.I. unit of radioactivity is
- Suppose for some reasons, radius of earth were to shrink by 1% of present value,
- Two capacitors of 10pF and 20pF are connected to 200V and 100V sources, respectively.
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The pair of quantities having same dimensions is
- An aicraft executes a horizontal loop of radius 1 km with a speed of 900 kmh⁻¹
- The S.I. unit of radioactivity is
- Suppose for some reasons, radius of earth were to shrink by 1% of present value,
- Two capacitors of 10pF and 20pF are connected to 200V and 100V sources, respectively.
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply