| ⇦ |
| ⇨ |
A transverse wave is represented by y = a sin (?t – kx). For what value of the wavelength is the wave velocity equal to the maximum particle velocity?
Options
(a) πA / 2
(b) π A
(c) 2π A
(d) A
Correct Answer:
2π A
Explanation:
y = A sin ( ?t – kx ) particle velocity,
vₚ = dy/ dt = A ? cos ( ?t – kx )
vₚ ₘₐₓ = A ? wave velocity = ? / k
A ? = ? / k i.e., A = 1/k But k = 2π / λ
λ = 2π A
Related Questions: - If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum
- A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
- In radioactive element, β-rays are emitted from
- A body of mass 0.5 kg travels in a straight line with velocity v=a x³/², where
- The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
Topics: Waves
(80)
Subject: Physics
(2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- If the ratio of amplitude of two superposed waves is 2:1, then the ratio of maximum
- A body of mass m=3.513 kg is moving along the x-axis with a speed of 5 m/s
- In radioactive element, β-rays are emitted from
- A body of mass 0.5 kg travels in a straight line with velocity v=a x³/², where
- The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain
Topics: Waves (80)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
18000+ students are using NEETLab to improve their score. What about you?
Solve Previous Year MCQs, Mock Tests, Topicwise Practice Tests, Identify Weak Topics, Formula Flash cards and much more is available in NEETLab Android App to improve your NEET score.
Share this page with your friends

Leave a Reply