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A total charge of 5µC is distributed uniformly on the surface of the thin walled semispherical cup. If the electric field strength at the centre of the hemisphere is 9×10⁸NC⁻¹, then the radius of the cup is
{1/4πε₀=9×10⁹N-m²C⁻²}
Options
(a) 5mm
(b) 10mm
(c) 5cm
(d) 10cm
Correct Answer:
5mm
Explanation:
No explanation available. Be the first to write the explanation for this question by commenting below.
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Topics: Electrostatics
(146)
Subject: Physics
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Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
- The earth is assumed to be a sphere of radius R. A platform is arranged at a height R
- The angle between the dipole moment and electric field at any point on the equatoria
- The time period of a mass suspended from a spring is T. If the spring is cut into four
- The time period of bar magnet is doubled when magnetic field is reduced
- Sodium and copper have work function 2.3 eV and 4.5 eV respectively
Topics: Electrostatics (146)
Subject: Physics (2479)
Important MCQs Based on Medical Entrance Examinations To Improve Your NEET Score
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